(4x^2+34x+40)/(x+7)

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Solution for (4x^2+34x+40)/(x+7) equation: 


D( x )

x+7 = 0

x+7 = 0

x+7 = 0

x+7 = 0 // - 7

x = -7

x in (-oo:-7) U (-7:+oo)

(4*x^2+34*x+40)/(x+7) = 0

4*x^2+34*x+40 = 0

2*(2*x^2+17*x+20) = 0

2*x^2+17*x+20 = 0

DELTA = 17^2-(2*4*20)

DELTA = 129

DELTA > 0

x = (129^(1/2)-17)/(2*2) or x = (-129^(1/2)-17)/(2*2)

x = (129^(1/2)-17)/4 or x = (-(129^(1/2)+17))/4

2*(x+(129^(1/2)+17)/4)*(x-((129^(1/2)-17)/4)) = 0

(2*(x+(129^(1/2)+17)/4)*(x-((129^(1/2)-17)/4)))/(x+7) = 0

( x+(129^(1/2)+17)/4 )

x+(129^(1/2)+17)/4 = 0 // - (129^(1/2)+17)/4

x = -((129^(1/2)+17)/4)

( x-((129^(1/2)-17)/4) )

x-((129^(1/2)-17)/4) = 0 // + (129^(1/2)-17)/4

x = (129^(1/2)-17)/4

x in { -((129^(1/2)+17)/4), (129^(1/2)-17)/4 }

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